Age Word Problem: Find the Father's and Son's Ages
A classic algebra problem, worked out step by step by Dr. E — with the full reasoning behind every move, a video walkthrough, and a free practice worksheet.
A father is 3 times as old as his son. In 12 years, the father will be twice as old as the son. Find their present ages.
Video solution coming soon. Dr. E walks through this exact problem on the whiteboard, step by step.
Subscribe on YouTube so you don't miss it →| Now | In 12 years | |
|---|---|---|
| Son | x | x + 12 |
| Father | 3x | 3x + 12 |
💡 Why this works — the habit to remember
Age problems feel wordy, but they're tame once you build the Now / Later table. Everybody ages by the same amount, so each "later" cell is just the "now" cell plus 12. The single equation always comes from the sentence about the future relationship.
Extension question: change "twice as old" to "the father is 30 years older than the son" and see which clue actually controls the answer.